Answer:
5 m/s² east
Explanation:
Acceleration is change in velocity over change in time. It can be expressed mathematically as:
[tex]\displaystyle{\vec a = \dfrac{\Delta \vec v}{\Delta t}}\\\\\displaystyle{\vec a = \dfrac{\vec v_2 - \vec v_1}{t_2-t_1}}[/tex]
Where [tex]\displaystyle{\vec v_2}[/tex] is final velocity, [tex]\displaystyle{\vec v_1}[/tex] is initial velocity, [tex]\displaystyle{t_2}[/tex] is final time and [tex]\displaystyle{t_1}[/tex] is initial time.
Therefore, from the problem, we know that:
- final velocity is 30 m/s east.
- initial velocity is 10 m/s east.
- final time is 4 seconds.
- initial time is 0 second.
Therefore:
[tex]\displaystyle{\vec a = \dfrac{30 \ \, \sf{m/s} \ \, east- 10 \ \, m/s \ \, east}{4 \ \, \sf{seconds}-0\ \, seconds}}\\\\\displaystyle{\vec a = \dfrac{20 \ \, \sf{m/s} \ \, east}{4 \ \, \sf{seconds}}}\\\\\displaystyle{\vec a = 5 \ \, \sf{m/s^2} \ \, \sf{east}}[/tex]
Therefore, acceleration will be 5 m/s² east.
