The slope of the line containing BC is [tex]\frac{-1}{2}[/tex].
Trapezium or Trapezoid is defined as a quadrilateral that have two parallel sides and two non-parallel sides.
Slope of a line is defined as tan(α) where α is the angle that line makes with positive x axis.
Two parallel lines have same slope.
In the given figure
right trapezoid ABCD , the lines BC and AD are parallel,
Hence they will have same slope.
Given line AD
[tex]y=\frac{-1}{2} x+10[/tex]...…..(1)
On comparing (1) with the slope intercept form of the line
y=mx+c , where m = slope and c =y-intercept (where the graph crosses the y-axis)
we get [tex]m=\frac{-1}{2}[/tex]
The slope of the line AD= -1/2 and since the line's AD and BC are parallel,
the slope of BC is also [tex]\frac{-1}{2}[/tex].
Therefore , the slope of the line containing bc is [tex]\frac{-1}{2}[/tex].
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