The coordinates of b are (6, -7)
We know that the midpoint formula,
The midpoint of line passing through points (m, n) and (p, q) is,
[tex](\frac{m+p}{2} ,\frac{n+q}{2} )[/tex]
For given question,
The midpoint of ab is m(7,-2).
We have been given the coordinates of a = (8,3)
We need to find the coordinates of b.
Let a = (x, y)
= (8, 3)
and the coordinates of b = (p, q)
Using midpoint formula,
m = [tex](\frac{x+p}{2} ,\frac{y+q}{2} )[/tex]
(7, -2) = [tex](\frac{8+p}{2} ,\frac{3+q}{2} )[/tex]
Comparing X-coordinates we have,
⇒ [tex]\frac{8+p}{2}=7[/tex]
⇒ 8 + p = 14
⇒ p = 6
Similarly, by comparing Y-coordinates we have,
⇒ [tex]\frac{3+q}{2} =-2[/tex]
⇒ 3 + q = -4
⇒ q = -7
This means, (p, q) = (6, -7)
Therefore, the coordinates of b are (6, -7)
Learn more about the midpoint formula here:
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