Vanadium and the oxide is V2O5.
What is the oxide?
We have the information that the element which has an atomic mass between 40 and 55 reacts with oxygen. This compound must e ionic so we can write; 2M + x/2O2 --->M2Ox
Mass of oxygen utilized in the reaction is; 3.708 g - 2.077 g = 1.631 g
Number of moles of oxygen used = 1.631 g/32g/mol = 0.051 moles
Number of moles of the metal = 2.077 g/M
Thus;
2.077 g/M * x/4 = 0.051 moles
2.077x/4M = 0.051 moles
2.077x = 0.204M
M = 2.077x /0.204
M = 10.181x
Given that x could be 4 or 5, we have to agree that x =5 which gives a mass of 50.93 thus M is Vanadium and the oxide is V2O5.
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