The velocity, V, of a specific object being dropped from a particular height, h, can be found by the radical function V - /2/a where a
represents the acceleration in At/sec?. If the acceleration due to gravity is 32.2 fu/sec?, at what height should you drop an object in order for it to
have a velocity of 80 ft/sec?
O
5,152 feet
O
99.4 feet
O
71.8 feet
0 d
1.5 feet

Respuesta :

The height should you drop an object in order for it to have a velocity of 80 ft/sec is: 99.4 feet.

Height

V = √2ha

80=√2(h)32.2

80²=√2(t) (32.2)²

6400=2(t) (32.2)²

Divide both sides by 32.2 to get 2t

6400/32.2=2(t) (32.2)/32.2

198.75776397=2(t)

Divide both sides by 2 to get t

198.75776397/2=2(t)/2

Hence,

99.4 feet

Therefore the height should you drop an object in order for it to have a velocity of 80 ft/sec is: 99.4 feet.

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