The probability that the first 7 flips will be heads and the remaining 8 flips will be tails if a fair coin is tossed 15 times is
Where H is heads and T is tails
We know that,
Probability of heads in a fair coin = 1/2
Probability of tails in a fair coin = 1/2
Hence,
Probability of heads for the first 7 heads = [tex](\frac{1}{2} )^{7}[/tex]
Probability of tails for the last 8 tails = [tex](\frac{1}{2} )^{8}[/tex]
Probability that the first 7 flips will be heads and the remaining 8 flips will be tails if a fair coin is tossed 15 times = [tex](\frac{1}{2} )^{7}*(\frac{1}{2} )^{8}[/tex].
To learn more about probability, here:-
https://brainly.com/question/11234923
#SPJ4
