Respuesta :
61.4 grams of glucose must be added to 250 grams of water heated to 40 degrees Celsius in order to produce a 54.0 torr vapor pressure solution.
Vapor pressure of water is = 55.3 torr (given)
We know that,
According to Raoult,s Law :
vapor pressure of solution = mole fraction of solvent (H2O) * vapor pressure of solvent (H2O)
Psolution = Xsolvent * Psolvent
Psolution = XH2O*PH2O
XH2O = 54.00 torr / 55.3 torr
XH2O = 0.976
mole fraction of solvent (H2O) = no. of moles of H2O in the solution / total no. of moles in the solution
XH2O = nH2O / nH2O + nglucose
0.976 = 250 g (mol/18.02g) / (250/18.02) mol + nglucose
nglucose = 0.341 mol
So, mass of glucose = 0.341 mol of glucose * molar mass of glucose
mglucose = 0.341 mol of glucose * (180.16g/mol)
mass of glucose = 61.4 grams of glucose
What is Raoult's law?
Raoult's Law relates the vapor pressure of a solution on the mole fraction of the solute added to a chemical solution.
Find more about vapor pressure at : brainly.com/question/14937177
#SPJ4
