The sequence of amino acids that would result from translating and transcribing a DNA template strand with the bases TACGCTAAT would be Met-Arg-Leu (Methionine Arginine Leucine).
As we know, a DNA has four bases such as adenine (A), thiamine (T), guanosine (G), and cytosine (C), but RNA has all three bases, such as A, G, and C, similar to DNA except for T.
Therefore, Instead of T, RNA has another base, uracil (U). The U can bind with A, and G can bind with C. So, the strand will generate m-RNA having the sequence AUGCGAUUA. Hence, an amino acid sequence is produced during translation while dividing the whole sequence into three tri-nucleotide sequences. Thus, the amino acids will be Met-Arg-Leu (Methionine Arginine Leucine).
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