By solving a linear equation, we conclude that after 3.57 hours, the prices of the two stocks are the same.
in how many hours will the prices of the two stocks be the same?
For stock A, the price started at $12.51 and it increased at a rate of $0.09 per hour. So after x hours, the price of stock A is:
A(x) = $12.51 + $0.09*x
For stock B, the price starts at $13.26 and it increases at a rate of $0.12 per hour, then the price after x hours is:
B(x) = $13.26 - $0.12*x
The price of the stocks is the same when:
A(x) = B(x), then we can solve the equation:
$12.51 + $0.09*x = $13.26 - $0.12*x
Now we can solve that linear equation for x:
$0.09*x + $0.12*x = $13.26 - $12.51 = $0.75
$0.21*x = $0.75
x = $0.75/$0.21 = 3.57
So, after 3.57 hours, the prices of the two stocks are the same.
If you want to learn more about linear equations:
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