Respuesta :
[tex]y=\frac{x}{7} +\frac{15}{7}[/tex]
How to find the equation of a passing line?
- The equation y = mx often denotes a straight line with a gradient of m that passes through the origin. Y = mx is the equation for a straight line with gradient m that passes through the origin.
- Y = mx + b is the equation for a line with a slope of m and a y-intercept of (0, b). In order to graph a line expressed in slope-intercept form: Draw the coordinate plane's y-intercept. To locate a different point on the line, use the slope.
- The three main types of linear equations are slope-intercept form, standard form, and point-slope form.
Given: [tex](-1,2)[/tex] and [tex](6,3).[/tex]
The slope of the line passing through[tex](x1,y1)[/tex] [tex](x2,y2)[/tex] is [tex]\frac{y^{2} }{x^{2} } -\frac{y^{1} }{x^{1} }[/tex]
The slope of our line[tex]=\frac{(3-2)}{(6+1)} =\frac{1}{7}[/tex]
Slope intercept from the equation would be [tex]y= 1/7 x +C[/tex]
Find C:
Since [tex](-1,2)[/tex] lies on the line, substitute these in the line equation
[tex]2 = \frac{1}{7(-1)} +c[/tex]
[tex]C=2+\frac{1}{7} =\frac{15}{7}[/tex]
Therefore, the equation in slope intercept form is[tex]y=\frac{x}{7} +\frac{15}{7}[/tex]
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