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A hotel builds an isosceles trapezoidal pool for children. It orders a tarp to cover the pool when not in use. What is the area of the tarp?

Trapezoid ABCD with base side AD labeled 15 feet, top side BC labeled 10 feet, and right side CD labeled 5 feet. Angle C measures 120 degrees.
To find the height, first find that is
. This means the height of the trapezoid is approximately
feet. So, the area of the tarp is approximately
square feet.

A hotel builds an isosceles trapezoidal pool for children It orders a tarp to cover the pool when not in use What is the area of the tarp Trapezoid ABCD with ba class=
A hotel builds an isosceles trapezoidal pool for children It orders a tarp to cover the pool when not in use What is the area of the tarp Trapezoid ABCD with ba class=
A hotel builds an isosceles trapezoidal pool for children It orders a tarp to cover the pool when not in use What is the area of the tarp Trapezoid ABCD with ba class=

Respuesta :

MrRoyal

The area of the tarp is 54.125 square feet

How to determine the measure of D?

From the figure in the question, we have the following angle measure:

DCE= 120

This means that:

<C = DCE - 90

Substitute the known values in the above equation

<C = 120 - 90

Evaluate the difference

<C = 30

The measure of D is then calculated as

<D = 90 - <C

This gives

<C = 90 - 30

Evaluate the difference

<C = 60

How to determine the height of the trapezoid?

Represent the height with h.

This is then calculated as:

sin(D) = h/5

This gives

sin(60) = h/5

Multiply both sides by h

h = 5 * sin(60)

Evaluate

h = 4.33

How to determine the area of the tarp?

This is calculated as:

A = 0.5 * (10 + 15) * 4.33

Evaluate

A = 54.125

Hence, the area of the tarp is 54.125 square feet

Read more about trapezoid at:

https://brainly.com/question/1463152

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