The maximum height is; 180 ft and the Total time in the air is 12 seconds
How to solve projectiles?
We are given the equation that represents the height of the rocket as;
d = 60t - 5t²
Taking the derivative of the formula gives us;
d' = 60 - 10t.
-10t represents the acceleration. The 60 represents the initial velocity.
Set 60 - 10t = 0 and solve for t to get;
t = 60/10 = 6seconds.
That's when the maximum height occurs. Plug that value of t into the original quadratic equation to get the maximum height.
d(6) = 60t - 5t²
d(6) = 60(6) - 5(6²)
d(6) = 180
So, maximum height is about 180 ft.
Thus, total time in air = 2 * 6 = 12 seconds
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