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43% of a sample of 100 visitors to a national park believes that additional funds should be used to preserve endangered species. what is the margin of sampling error for a 95% confidence interval?

Respuesta :

The margin of sampling error for a 95% confidence interval is 9.7%

How to find the Margin of Error?

The formula for margin of error here is;

E = z√(p(1 - p)/N)

where;

n is sample size

z is the z score

p is the sample proportion

z-score for a 95% confidence interval from tables is 1.96.

We are given;

p = 43% = 0.43

n = 100

Thus;

E = 1.96√(0.43(1 - 0.43)/100)

E =  0.097 = 9.7%

Thus, we can conclude that  the margin of sampling error for a 95% confidence interval is 9.7%

Read more about Margin of Error at; https://brainly.com/question/24323979

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