Which one of the following linear inequalities is graphed in the xy plane above

The linear inequality that is graphed in the xy plane is: C. 2x + 3y ≤ 4.
Values in the shaded part are the solution of a a linear inequality. Thus, a dotted or dashed line is used on the graph when the inequality sign is either "<" or ">". On the other hand, when a line that is not dotted or dashed is used when the inequality sign is either "≤" or "≥". These lines, dotted or not are the boundary lines.
Also, when the shaded area is above the boundary line, the sign "≥" or ">" is used. When the shaded part is beneath the boundary line, "≤" or "<" is used in the linear inequality.
The graph given has a boundary line that is not dashed or dotted, and also, the shaded part is beneath the boundary line. Therefore, the inequality sign to use is "≤".
Find the slope:
Slope (m) = rise/run = -4/3 / 2 = -4/6
m = -2/3
y-intercept (b) = 4/3.
Substitute m = -2/3 and b = 4/3 into y ≤ mx + b:
y ≤ -2/3x + 4/3
Rewrite
3y ≤ -2x + 4
2x + 3y ≤ 4
The answer is: C. 2x + 3y ≤ 4.
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