The limit of f(x) as x goes to 1 will not exist for function III.
What is a limit?
A limit is given by the value of function f(x) as x tends to a value. For a function with different lateral limits at a point x = a, the limit will not exist at the point x = a. Additionally, the limit may not exist at a point if there is a non-removeable discontinuity.
Factoring the function 1, the limit will be given as follows:
[tex]\lim_{x \rightarrow 1} \frac{1 - x^2}{x - 1} = \lim_{x \rightarrow 1} \frac{(1 - x)(1 + x)}{x - 1} = \lim_{x \rightarrow 1} -(1 +x) = -2[/tex]
Hence the limit exists.
Factoring the function 2, the limit will be given as follows:
[tex]\lim_{x \rightarrow 1} \frac{x^2 - x^3}{x^2 - 1} = \lim_{x \rightarrow 1} \frac{x^2(1 - x)}{(x - 1)(x + 1)} = \lim_{x \rightarrow 1} -\frac{x^2}{x + 1} = -\frac{1}{2}[/tex]
Hence the limit exists.
Factoring the function 3, the limit will be given as follows:
[tex]\lim_{x \rightarrow 1} \frac{x + 1}{x^2 - 1} = \lim_{x \rightarrow 1} \frac{x + 1}{(x - 1)(x + 1)} = \lim_{x \rightarrow 1} \frac{1}{x - 1}[/tex]
Non-revemoveable discontinuity, as we can't remove x - 1 for the denominator, ence the limit does not exist for function III.
More can be learned about limits at https://brainly.com/question/26270080
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