The molarity of the solution is 0.32 M
Calculation,
Molarity of the solution is the total number of moles present in volume in liter.
molarity = number of moles/volume in liter = n/V ...(i)
Number of moles of sulfuric acid = given mass/molar mass
Number of moles of sulfuric acid (n) = 16g/98.079g/mol = 0.16 mole
Volume of the solution (V) = 0.5 L
Putting the value of volume and number of moles in equation (i) we get,
molarity = 0.16 mol/0.5 L = 0.32 mol/L = 0.32 M
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