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If the average score is 122 with a standard deviation of 35,
what percentage of students scored below 67? Answers are
rounded to the nearest whole percent.
O a.) 90%
O b.) 6%
O c.) 10%
O d.) 94%

Respuesta :

tushargupta0691

 94% of students scored less than 67 .

Z-score is measured in terms of standard deviations from the mean. If a Z-score is 0, it indicates that the data point's score is identical to the mean score. A Z-score of 1.0 would indicate a value that is one standard deviation from the mean

Given :-

Mean score, μ = 122

Standard deviation, σ = 35

The fraction of students who scored less than 67 can be found out by z score where z score is  Z = (x - μ) / σ

For x = 67

Z = (67 - 122)/35 = -1.57

P-value from Z-Table:

P(x>67) = 1 - P(x<67) = 0.94196

Thus approximately  94% of students scored less than 67 .

Learn more about Z Score here :

https://brainly.com/question/15016913

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