The molecular of the compound will be-(H₂CO₃)1= H₂CO₃
The given molecule has the molecular formula H2CO3, also known as Carbonic acid.
Given that-
Consequently,
H= 3.3%.
C=19.3%
O =77.4%
Number of H moles = 3.3/1 = 3.3
Number of C moles = 19.3/12 = 1.60
Number of O moles = 77.4/16 = 4.83
As a result, the ratio of C, H, and O atoms is 3.3: 1.60: 4.83.
Divide by the amount you obtain that is the smallest: 3.3/1.60; 1.60/1.60; 4.83/1.60 = 2: 1: 3
H2CO3 is the empirical formula.
Let (H2CO3)n be the molecular formula.
A molecular formula is a chemical formula that specifies how many atoms of each element there are in each molecule of a given substance.
Molar mass thus equals (21+112+3X16)n = 62n.
As per the inquiry, 62n = 60
alternatively, n= 0.96 (round figure is 1)
Therefore, carbonic acid is the chemical whose molecular formula is (H2CO3)1=H2CO3.
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