In order to determine the number of different groups of three players that are possible for Coach Bennet to select from, we would use a mathematical model referred to as combination.
Mathematically, combination is given by this mathematical equation:
[tex]_nC_r = \frac{n!}{r!(n-r)!}[/tex]
Where:
Substituting the given parameters into the formula, we have;
Number of groups = (⁶C₃ × ⁸C₀) + (⁶C₂ × ⁸C₁) + (⁶C₁ × ⁸C₂) + (⁶C₀ × ⁸C₃)
Number of groups = 20 + 120 + 168 + 56
Number of groups = 364 different groups.
Therefore, there are 364 different groups of three players possible for Coach Bennet to select.
In conclusion, we can infer and logically deduce that this is a combination because the order in which the players are selected isn't important.
Read more on combination here: brainly.com/question/17139330
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Complete Question:
In this activity, you will apply your understanding of permutations and combinations to calculate probabilities. Use the information in this scenario to answer the questions that follow. Coach Bennet’s high school basketball team has 14 players, consisting of six juniors and eight seniors. Coach Bennet must select three players from the team to participate in a summer basketball clinic.
How many different groups of three players are possible for Coach Bennet to select?
