The reaction of 75.0 g p4 with excess chlorine gas produces 110 g pcl3 in lab. The percent yield for the reaction is 32.7%.
P4+ 6 Cl2 — 4PCl3
moles of P4 in 75 g
n=m/M
where n = moles; m= mass; M = molar mass
M(P4) = 4× 30.974 g/ mol
P = 123.896g/mol
n can be given as
n(P4) = (75) / 123.896
= 0.60535 mol
Total=
0.60535 mol P4 × 4 mol/1 mol P4
= 2.4214 mol PCl3
mass of PCl3
m= n×M
M = 30.974 g/mol P+(3× 35.45g/mol Cl)
= 137.32g/mol
m= 2.4212 mol× 137.32g/mol
=333 g
The yield of PCl3 is 333 g.
The theoretical yield of PCl3 is 110 g.
percent yield can be given as
(percent yield/ theoretical yield) × 100
%yield = (333/110) ×100
Thus, the percent yield of PCl3 is 32.7%.
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