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In a survey of 2035 workers, 73% reported working out 3 or more days a week. What is the margin of error? What is the interval that is likely to contain the exact percent of all people who work out 3 or more days a week? Show all work.

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In a survey of 2035 workers 73 reported working out 3 or more days a week What is the margin of error What is the interval that is likely to contain the exact p class=

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The margin of error is 1.9%. and the interval that likely contains the true percent of all people who work out 3 or more days a week is: (71.1%, 74.9%)

What is the Margin of Error?

Margin of error is the critical value (t score or z score) multiplied by the standard error (standard deviation of the sample). Thus;

ME = Critical value × S.E

Since n > 30, we can use the z-score as the critical value.

Assuming 95% confidence level, then z = 1.96

The standard error for a proportion is given by the formula:

s = √(p (1 − p) / n)

We are given;

p = 0.73

n = 2035:

Thus;

s = √(0.73 (1 − 0.73) / 2035)

s = 0.0098

Thus, the margin of error is:

ME = 1.96 × 0.0098

ME = 0.019

The margin of error is 1.9%.  

The interval that likely contains the true percent of all people who work out 3 or more days a week is:

73% ± 1.9% = (71.1%, 74.9%)

Read more about Margin of Error at; https://brainly.com/question/10218601

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