ratliffhaley2023
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The mean salary at a local industrial plant is $⁢29,300 with a standard deviation of $⁢5400. The median salary is $⁢24,500 and the 63rd percentile is $⁢29,600.
Step 1 of 5: Based on the given information, determine if the following statement is true or false.
Approximately 63% of the salaries are less than or equal to $29,600
Step 2 of 5: Based on the given information, determine if the following statement is true or false.
Joe's salary of $⁢39,320 is 1.80 standard deviations above the mean.
Step 3 of 5: Based on the given information, determine if the following statement is true or false.
The percentile rank of $⁢25,000 is 50.
Step 4 of 5: Based on the given information, determine if the following statement is true or false.
Approximately 13% of the salaries are between $⁢29,300 and $⁢29,600.
Step 5 of 5: If Tom's salary has a z-score of 0.5, how much does he earn (in dollars)?

Respuesta :

The true and false statement about the mean salary is illustrated below.

How to illustrate the information?

The true false statement about the mean salary include:

  • Approximately 63% of the salaries are less than or equal to $29,600
  • Joe's salary of $⁢39,320 is 1.80 standard deviations above the mean.
  • The percentile rank of $⁢25,000 is 50.
  • Approximately 13% of the salaries are between $⁢29,300 and $⁢29,600.

When Tom's salary has a z-score of 0.5, the amount that he earns will be:

0.5 = (x - 29300)/5400

0.5 × 5400 = x - 29300

2700 = x - 29300

x = 29300 + 2700.

x = 32000

The amount he earns is 32000.

Learn more about mean on:

brainly.com/question/1136789

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