There are approximately 6.02 × 10²³ atoms of phosphorus in one mole of 30.974 grams of phosphorus (option A).
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number. That is;
no of atoms = no of moles × 6.02 × 10²³
According to this question, there are 30.974 grams of phosphorus in one mole of phosphorus. The number of atoms can be calculated as follows:
no of moles of P = 30.974g ÷ 31g/mol = 0.99mol
number of atoms = 0.99 mol × 6.02 × 10²³
number of atoms = 6.02 × 10²³ atoms
Therefore, there are approximately 6.02 × 10²³ atoms of phosphorus in one mole of 30.974 grams of phosphorus.
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