The equation y = 1/3x - 2 passes through the diagonals of ZDRN
How to determine the end result?
The points are given as:
Z = (-3, -1)
D= (3, -1)
R = (3, -3)
N = (-3, -3)
The equation of the line is given as:
y = 1/3x - 2
When the points and the line equation are plotted in a graph on the same coordinate (see attachment), we can see that the equation y = 1/3x - 2 passes through the points Z = (-3, -1) and N = (-3, -3)
These points are the diagonals of the shape formed by the four points
Hence, the equation y = 1/3x - 2 passes through the diagonals of ZDRN
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