Use the FOIL method to evaluate the expression:

Answer:
[tex]\sf b.) \ 1 +2\sqrt{7}[/tex]
Explanation:
Foil method: (a + b)(c + d) = ac + ad + bc + bd
Solving steps:
[tex](4 - \sqrt{7} )(2 + \sqrt{7} )[/tex]
[tex](4)(2) + 4(\sqrt{7} ) + (-\sqrt{7} )(2) + (-\sqrt{7} )(\sqrt{7} )[/tex]
[tex]8 + 4\sqrt{7} - 2\sqrt{7} - 7[/tex]
[tex]8 -7 + 4\sqrt{7} - 2\sqrt{7}[/tex]
[tex]1 +2\sqrt{7}[/tex]
option b) 1 + 2√7
Foil property method :-
[tex] \red{ \boxed{ \orange{ \rm (a + b)(c + d) = ac + ad + bc + bd}}}[/tex]
then, on substituting the values,
[tex]\sf⇒ \: \: 8 + 4 \sqrt{7} - 2 \sqrt{7} - 7[/tex]
[tex]\sf⇒ \: \: \green{ \underline{\bold{ \red{1 + 2 \sqrt{7} }}}}[/tex]