Respuesta :

rorycampbell0721

Answer:

x = ±√7, ±i√2

Step-by-step explanation:

[tex]x^4-5x^2-14=0\\(x^2-7)(x^2+2)=0\\[/tex]

[tex]x^2 - 7 = 0[/tex] or [tex]x^2 + 2 = 0\\[/tex]

x^2 - 7 = 0

x^2 = 7

x = ±√7

or x^2 + 2 = 0

x^2 = -2

x = ±i√2

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