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(02.01 LC)

PLEASE HURRY
ACAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps
point C to C' (3, 2). Find the coordinates of A' and R' under this
translation. (6 points)
A. A' (4, -2); R' (2, -1)
B. A' (-2, 2); R' (2,-2)
C. A' (2, -1); R' (4, -2)
D. A' (-1, 0); R' (-2, 2)

Respuesta :

Answer: Choice C

A' (2, -1); R' (4, -2)

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Explanation:

Going from C(2,4) to C'(3,2) means we do these two things (in any order)

  • Shift 1 unit to the right
  • Shift 2 units down

We can write that rule using the notation [tex](x,y) \to (x+1, y-2)[/tex]

Whatever the x coordinate is, add 1 to it. Also subtract 2 from the y coordinate.

Here are the steps you could show how point A(1,1) is moving

[tex](x,y) \to (x+1, y-2)\\\\(1,1) \to (1+1, 1-2)\\\\(1,1) \to (2, -1)\\\\[/tex]

Therefore, the point A(1,1) will move to A'(2, -1)

And the point R(3,0) moves to R'(4, -2) through similar steps.

[tex](x,y) \to (x+1, y-2)\\\\(3,0) \to (3+1, 0-2)\\\\(3,0) \to (4, -2)\\\\[/tex]

The diagram is shown below.

Ver imagen jimthompson5910

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