50 POINTS+brainliest but reposting again because my points were used last time: How do you graph a quadratic equation in vertex form when the equation is a perfect square? Use x² -4x+4 as an example
you will be reported if your answer is absurd
Answer: If it is a perfect square, k=0 in the form y=a(x-h) ^2+k. Step-by-step explanation: x^2-4x+4=(×-2) ^2, meaning that the vertex is at the point (2,0).
