Let's take this problem step by step:
To find the ordered pair of the system:
⇒ must set both equations equal to each other
⇒ solve for 'x'
Let's solve:
[tex]x^2-2x+3=-2x+12\\x^2-2x+2x+3-12\\x^2-9=0\\(x+3)(x-3)=0[/tex]
Let's find the x-values:
[tex](x+3)=0\\x=-3\\\\(x-3)=0\\x+3[/tex]
Let's find f(x)'s value for each 'x':
[tex]x=-3\\f(-3)=-2(-3)+12=6+12=18\\\\x=3\\f(3)=-2(3)+12=-6+12=6[/tex]
Answer: (3, 6), (-3,18)
Hope that helps!
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