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A 50-kg block is at rest on a 15o slope. A force of 250 N is acting on the block up the slope parallel to it. If the block does not slide up the slope, what is the minimum value of the coefficient of static friction between the block and the slope

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onyebuchinnaji

The minimum value of the coefficient of static friction between the block and the slope is 0.53.

Minimum coefficient of static friction

Apply Newton's second law of motion;

F - μFs = 0

μFs = F

where;

  • μ is coefficient of static friction
  • Fs is frictional force
  • F is applied force

μ = F/Fs

μ = F/(mgcosθ)

μ = (250)/(50 x 9.8 x cos15)

μ = 0.53

Thus, the minimum value of the coefficient of static friction between the block and the slope is 0.53.

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