mclairegill08
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PLEASE HELP ASAP!!!!!!!!!
The terminal ray of angle θ drawn in standard position passes through (1,−3).

What is the value of cscθ?

Enter your answer in the box. Enter your answer in simplest form.

csc0=

Respuesta :

Medunno13

The radius of the circle is

[tex] \sqrt{ {1}^{2} + {( - 3)}^{2} } = \sqrt{10} [/tex]

meaning that

[tex] \sin( \theta ) = \frac{ - 3}{ \sqrt{10} } [/tex]

Thus,

[tex] \csc \theta = - \frac{ \sqrt{10} }{3} [/tex]

The value of csc θ is  √10/ (-3).

What is trigonometry?

Trigonometry is a branch of mathematics that studies relationships between the sides and angles of triangles.

As,

(1,−3) is in quadrant 4 and csc is negative.

Using Pythagoras,

H=√ 1² + (-3)²

H= √10

So, cosec θ= H/P

                  = √10/ (-3)

Learn more about this concept here:

https://brainly.com/question/17139523

#SPJ1

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