The mass of manganese oxide (MnO2) that is needed to generate 126.0 g Zn(OH)2 is 220.56 g.
Mass of manganese oxide needed
The mass of MnO2 that is needed to generate 126.0 g Zn(OH)2 is calculated as follows;
Zn + 2MnO₂ + H₂O → Zn(OH)2 + Mn₂O3
From the reaction above;
2(87 g/mol of MnO₂) ---------> 99.4 g/mol of Zn(OH)2
174 ---------------------> 99.4
? -------------------------> 126
= (126 x 174)/99.4
= 220.56 g
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