in a titration, 14.5cm3 of nitric acid, HNO3 neutralised exactly 25cm3 of 0.05 mol/dm3 sodium hydroxide, NaOH

calculate the concentration of the nitric acid solution in mol/dm3
Calculate the concentration of the nitric acid in g/dm3

Respuesta :

The concentration of the nitric acid solution is 0.0862 mol/[tex]dm^3[/tex] and the concentration of the nitric acid in g/[tex]dm^3[/tex] is 5.431 g/[tex]dm^3[/tex].

What is titration?

A titration is a technique where a solution of known concentration is used to determine the concentration of an unknown solution.

According to the neutralization law,

[tex]n_1M_1V_1 = n_2M_2V_2[/tex]

[tex]n_1[/tex]is the basicity of [tex]HNO_3[/tex] =1

[tex]M_1[/tex] is the molarity of [tex]HNO_3[/tex] =0.05 mol/[tex]dm^3[/tex]

[tex]V_1[/tex] is the volume of [tex]HNO_3[/tex] solution = 25[tex]cm^3[/tex]

[tex]n_2[/tex] is the acidity of NaOH =1

[tex]M_2[/tex] is the molarity of NaOH =?

[tex]V_2[/tex] is the volume of NaOH solution =14.5[tex]cm^3[/tex]

Putting in the values we get:

[tex]n_1M_1V_1 = n_2M_2V_2[/tex]

1 x 0.05 mol/[tex]dm^3[/tex] x 25cm^3 = 1 x [tex]M_2[/tex] x 14.5[tex]cm^3[/tex]

[tex]M_2[/tex] = 0.0862 mol/[tex]dm^3[/tex]

Hence. the concentration of the nitric acid solution in  0.0862 mol/[tex]dm^3[/tex] and the concentration of the nitric acid in g/dm3 is 0.0862 x63.01 g/[tex]dm^3[/tex]= 5.431 g/[tex]dm^3[/tex].

Learn more about the titration here:

https://brainly.com/question/22138555

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