The concentration of the nitric acid solution is 0.0862 mol/[tex]dm^3[/tex] and the concentration of the nitric acid in g/[tex]dm^3[/tex] is 5.431 g/[tex]dm^3[/tex].
A titration is a technique where a solution of known concentration is used to determine the concentration of an unknown solution.
According to the neutralization law,
[tex]n_1M_1V_1 = n_2M_2V_2[/tex]
[tex]n_1[/tex]is the basicity of [tex]HNO_3[/tex] =1
[tex]M_1[/tex] is the molarity of [tex]HNO_3[/tex] =0.05 mol/[tex]dm^3[/tex]
[tex]V_1[/tex] is the volume of [tex]HNO_3[/tex] solution = 25[tex]cm^3[/tex]
[tex]n_2[/tex] is the acidity of NaOH =1
[tex]M_2[/tex] is the molarity of NaOH =?
[tex]V_2[/tex] is the volume of NaOH solution =14.5[tex]cm^3[/tex]
Putting in the values we get:
[tex]n_1M_1V_1 = n_2M_2V_2[/tex]
1 x 0.05 mol/[tex]dm^3[/tex] x 25cm^3 = 1 x [tex]M_2[/tex] x 14.5[tex]cm^3[/tex]
[tex]M_2[/tex] = 0.0862 mol/[tex]dm^3[/tex]
Hence. the concentration of the nitric acid solution in 0.0862 mol/[tex]dm^3[/tex] and the concentration of the nitric acid in g/dm3 is 0.0862 x63.01 g/[tex]dm^3[/tex]= 5.431 g/[tex]dm^3[/tex].
Learn more about the titration here:
https://brainly.com/question/22138555
#SPJ1