Answer:
[tex]2\sqrt{x+1}-3\\domain:[-1, \infty)[/tex]
Step-by-step explanation:
[tex]g(h(x)) = 2(\sqrt{x+1})-3\\g(h(x)) = 2\sqrt{x+1} - 3\\[/tex]
the function is only defined when (x+1) >= 0 (since square root) so the domain is when x >= -1
