The net of an isosceles triangular prism is shown. What is the surface area, in square units, of the triangular prism?

Three rectangles are shown, one below the other. The middle rectangle has a width of 6 units, and, along each width, is a triangle with a height of 4 units. The length of the lowermost rectangle is 8 units and its width is 5 units.

104 units2
132 units2
152 units2
168 units2

Respuesta :

Here, the surface area, in square units, of the triangular prism is 152 units².

We know that the area of any triangle can be calculated as

Area = 1/2 * base * height

The area of any rectangular figure can be calculated as

Area = length * width

Here, the length of the rectangular portion of the prism is 8 units.

The width of the lowermost rectangle is 5 units.

The area of the uppermost rectangle = the area of the lowermost rectangle = 8 * 5 units² = 40 units²

Again the width of the middle rectangle is 6 units.

So, the area of the middle rectangle = 6 * 8 units² = 48 units²

Now, the height and base of the triangles are 4 and 6 respectively.

So, the area of the left-hand side triangle = the area of the right-hand side triangle = 2 * (1/2) * 4 * (6/2) units² = 1 * 4 * 3 units² = 12 units²

Then the area of the triangular prism = area of rectangular portion + area of triangular portion = (2 * 40 + 48) + (2 * 12) units² = (80 + 48) + 24 units² = 128 + 24 units² = 152 units²

Therefore the surface area, in square units, of the triangular prism is 152 units². So, Option C is correct.

Learn more about the area here -

https://brainly.com/question/3867236

#SPJ10