11/36 would be the probability of getting 4 , when two dice are thrown simultaneously.
As there are 6 faces of die,
So Probability of Not getting four in one dice = [tex]5/6[/tex]
As both events are mutually exclusive, the probability of not getting four in two dice = [tex](5/6) * (5/6) = 25/36[/tex]
So probability of getting at least one four is = [tex]1-(25/36) = 11/36[/tex]
So probability = [tex]11/36[/tex]
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