Respuesta :

Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.

Normality comes out to be 8.11

Given

  • Mass of solute: 1000g
  • Volume of solution (V): 5000 ml = 5 liters
  • Equivalent mass of solute (E) = molar mass / n-factor

n-factor for [tex]Al_{2}S_{3}[/tex] is 6 and molar mass is 148g

So, on calculating equivalent mass is equal to 24.66g

FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)

                                           N=[tex]\frac{1000}{24.66*5}[/tex]

                                          N=8.11

Therefore, normality of 1 kg aluminum sulfide is 8.11

Learn more about normality here https://brainly.com/question/25507216

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