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Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.

x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Respuesta :

The correct simplified inequality is - 6x + 15 < 10 - 5x and the number line representation is "an open circle is at 5 and a bold line starts at 5 and is pointing to the right".

The given inequality is -3(2x - 5) < 5(2 - x)

We need to simplify the inequality.

What is inequality?

In mathematics, inequality is a statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.

Consider LHS and simplify -3(2x - 5) = -3(2x)-5(-3)

⇒ -3(2x - 5) = - 6x + 15 [∵(-)(-) = (+)]

Consider RHS and simplify 5(2 - x) = 5(2) + 5(-x)

⇒5(2 - x) = 10 - 5x [∵(+)(-) = (-)]

Now, - 6x + 15 < 10 - 5x

By subtracting 15 from both sides, we get

- 6x < -5 - 5x

By adding 5x to both sides, we get - x < - 5

The coefficient of x is -1. So, divide both sides by -1

Then we get x > 5

Hence, the correct simplified inequality is - 6x + 15 < 10 - 5x and the number line representation is "an open circle is at 5 and a bold line starts at 5 and is pointing to the right".

To learn more about inequalities visit:

https://brainly.com/question/20383699.

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