Answer:
55.5g of calcium chloride is produced in the reaction.
Explanation:
To calculate the amount of calcium chloride.
The reaction of calcium carbonate with hydrochloride acid gives calcium chloride
CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O
Mass of calcium carbonate (CaCO₃)= 50.0g
Molecular mass of CaCO₃ = Ca + C + O₃
= 40+ 12 + 3(16) = 100g
No of moles of calcium carbonate CaCO₃ = given mass / molecular mass
= 50g/ 100
= 0.5 moles
Molecular mass of calcium chloride = 40+ 2(35.5)=(40+71.0)= 111g/mol
1 mole of calcium carbonate gives = 1 mole of calcium chloride
0.5 moles of calcium carbonate gives= 0.5 × 111g/mole
= 55.5g
To learn more about moles, grams and molecular mass, refer to-
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