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A researcher conducts an between-subjects study examining the
effectiveness of a memory enhancement program at an assisted living
facility for elderly adults. One group of residents is selected to
participate in the program, and a second group of participants serves as
a control group. After 6 weeks, the researcher reports a combined score
measuring memory for each individual. The data are:
Control
Exercise
n = 10
M = 12
SS = 120.5

n=15
M= 15.5
SS = 190.0
a) Does the exercise program have a significant effect? Use a two
tailed test with an alpha level of .05
b) Compute Cohen's d to measure the size of the treatment effect

Respuesta :

abiolataiwo2015

H0: µ1 = µ2; The exercise program do not have significant effect on physical fitness, H1: µ1 =/ µ2; the exercise program had a significant effect on physical fitness and the  Estimated Cohen's d is 0.82.

Hypothesis

A. Significant effect

H0: µ1 = µ2

Based on the above hypothesis the exercise program does not have significant effect on physical fitness

H1: µ1 =/ µ2

Based on the above hypothesis the exercise program had a significant effect on physical fitness


Pooled variance: sp2 = (190 + 120.5/(15-1) + (10-1)

Pooled variance: sp2 = 310.5/23

Pooled variance: sp2 =13.5

Estimated standard error ( sM1-M2):

sM1-M2 =√13.5/15 +13.5/10

sM1-M2 =√2.25

sM1-M2 = 1.5

Tailed test (t)

t = (15.5 - 12)/1.5

t=3.5/1.5

t= 2.33

B. Estimated Cohen's d:

Estimated Cohen's d  = 3/√13.5

Estimated Cohen's d = 3/3.67

Estimated Cohen's d= 0.817

Estimated Cohen's d= 0.82 (Approximately); this is a large effect.

Conclusion demonstrating how the outcome of the hypothesis test would tend to appear in a research report is:  (Reject H0). Because the  group exercise program tend to have a significant effect on the physical fitness of elderly adults, t = 2.33, p <.05, d = 0.82.

Learn more about hypothesis here:https://brainly.com/question/15980493

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