Answer: [tex](x-10)^{2}+(y+3)^{2}=16[/tex]
Step-by-step explanation:
We know the center of the original circle is (-6, -3). After reflecting this over the line x=2, the new center is now (10, -3).
Thus, the equation of the circle is [tex](x-10)^{2}+(y+3)^{2}=16[/tex].