93.80 % is the per cent yield of the reaction [tex]Fe_2O_3(s)+3CO(g)[/tex] → [tex]2Fe(s)+3CO_2(g)[/tex].
A mole is a very important unit of measurement that chemists use. A mole of something means you have 602,214,076,000,000,000,000,000 of that thing, like how having a dozen eggs means you have twelve eggs.
[tex]Fe_2O_3(s)+3CO(g)[/tex] → [tex]2Fe(s)+3CO_2(g)[/tex]
[tex]50.5 g Fe_2O_3[/tex] x ([tex]1 mol of Fe_2O_3[/tex] ÷ [tex]159.69 g Fe_2O_3[/tex]) x ([tex]2 mol\; of Fe[/tex] ÷ [tex]1 mol Fe 34.97 g Fe[/tex])
[tex]% of yield = \frac{Practical X 100}{Theoretical}[/tex][tex]Percentage \;of \;yield = \frac{Practical X 100}{Theoretical}[/tex]
[tex]Percentage\; of yield = \frac{32.8 X 100}{34.97}[/tex]
= 93.80 %
Hence, 93.80 % is the per cent yield of the reaction.
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