correct, is Decay and the initial amount is 13000, rate is 25%
[tex]\qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^x\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &13000\\ r=rate\to 25\%\to \frac{25}{100}\dotfill &0.25\\ x=years \end{cases} \\\\\\ A=13000(1 - 0.25)^{x}\implies \boxed{A=13000(0.75)^x} \\\\\\ \stackrel{\textit{after 3 years}}{A=13000(0.75)^3}\implies A\approx 5484.38~\hfill \stackrel{\textit{after 8 years}}{A=13000(0.75)^8}\implies A\approx 1301.47[/tex]
