Answer:
Vertex: (0,-3)
Radius: 4
Step-by-step explanation:
Complete the square
[tex]x^2+y^2+6y=7\\\\x^2+y^2+6y+9=7+9\\\\x^2+(y+3)^2=16[/tex]
The equation of a circle takes the form of [tex](x-h)^2+(y-k)^2=r^2[/tex] where its center is [tex](h,k)[/tex] and its radius is [tex]r[/tex].
Hence, the vertex is [tex](0,-3)[/tex] and the radius is [tex]4[/tex].
