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Solve |7x +42| = 14x. Identify the solution and an extraneous solution.
A. Solution: x = -2;
extraneous solution: x = 6
B. Solution: x = 6;
extraneous solution: a = -6
C. Solution: x = 6;
extraneous solution: x = -2
D. Solution: x = = 2;
extraneous solution: a = -6

Respuesta :

10n31y

First Case

[tex]|7x+42|=14x\\\\7x+42=14x\\\\42=7x\\\\6=x[/tex]

Second case

[tex]-|7x+42|=14x\\\\-7x-42=14x\\\\-42=21x\\\\-2=x[/tex]

Verify into first case

[tex]|7(6)+42|=14(6)\\\\|84|=84\\\\84=84\\\\LS=RS[/tex]

[tex]|7(-2)+42|=14(-2)\\\\28\neq -28\\\\LS\neq RS[/tex]

The solution is 6 and the extraneous solution is -2, which makes the answer C.

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