28. use the first equation in section iv for this problem. k = - u_{g} , g=6.67*10^ -11 .m^ 3 kg^-1 s^-2 and m = 3.2 * 10 ^ 23 * kg . find y in terms of r.

Respuesta :

When, the mass and gravitational constant is provided, the  velocity v in terms of r is 6.534 x 10⁶ r^(-1/2) m/s.

What is gravity?

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The gravitational potential energy is directly proportional to the negative of product of masses of the object and inversely proportional to the distance between them.

U = - GMm/r

From the equation 1, k =-Ug

where k = Kinetic energy = 1/2mv²

here, m is the mass of the object, v is the velocity and g is the grvaitational acceleration.

1/2mv² = -(GMm/r) g

v = sq rt(2GM/r)

Given is the mass M =  3.2 x 10²³ kg , gravitational constant G = 6.67 x 10⁻¹¹ m³/kg.s²

Substitute the values and calculate the velocity v,

v = sq rt [( 2 x6.67 x 10⁻¹¹ x  3.2 x 10²³) / r]

v = 6.534 x 10⁶ r^(-1/2) m/s

Thus, the value of velocity v in terms of r is 6.534 x 10⁶ r^(-1/2) m/s.

Learn more about gravity.

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