The magnitude of the frictional force opposing the applied force is 50 N.
The friction is caused due to the relative motion between two uneven contacting surfaces.
Given is the mass of trunk m = 20kg, kinetic coefficient of friction μ = 0.255.
The normal force acting on the trunk N = mg
N = 20 kg x 9.81m /s²
N = 196.2 Newton
The friction force is
f =μN
f = 0.255 x 196.2
f =50.031 N
Thus, the magnitude of the frictional force opposing the applied force is approximately 50N.
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