Respuesta :

loneguy

[tex]4\left(\sqrt[5]{x^2 y} \right) +3 \left( \sqrt[5]{x^2 y} \right)\\\\=(4+3) \left( \sqrt[5]{x^2 y} \right)\\\\=7 \left( \sqrt[5]{x^2 y} \right)[/tex]

MalakYaqoot

Answer:

[tex]7(\sqrt[ 5 ]{ { x }^{ 2 } y })[/tex]

Step-by-step explanation:

The equation:

[tex]4 \sqrt[ 5 ]{ { x }^{ 2 } y } +3 \sqrt[ 5 ]{ { x }^{ 2 } y } [/tex]

1) Collect like terms by adding their coefficients ( [tex]3[/tex] and [tex]4[/tex])

[tex](3+4)\sqrt[ 5 ]{ { x }^{ 2 } y }[/tex]

2) Calculate

[tex]7(\sqrt[ 5 ]{ { x }^{ 2 } y })[/tex]

Otras preguntas