Respuesta :
Answer:
D = √193 units
or
D = 13.892 units
Step-by-step explanation:
Given:
(7, 4) and (-5, -3)
Calculate the distance
Solution:
[tex] \rm \: Distance (D) = \sqrt{( x_{2} - x_{1}) {}^{2} + (y_{2} - y_{1) {}^{2} }} [/tex]
Now, substitute the values given:
[tex] \rm \: D = \sqrt{ \{( - 5) - 7 \}^{2} + \{( - 3) - 4 {}^{} \} {}^{2} } [/tex]
[tex] \rm \: D = \sqrt{ \{12 \}^{2} + \{( - 3) - 4 {}^{} \} {}^{2} } [/tex]
[tex] \rm \: D = \sqrt{ 144 + \{( - 3) - 4 {}^{} \} {}^{2} } [/tex]
[tex]\rm D = \sqrt{144 + \{ 7\}{}^{2} } [/tex]
[tex] \rm \: D = \sqrt{144 + 49} [/tex]
[tex] \boxed{\rm \: D = \sqrt{193}} [/tex]
[tex] \boxed{\rm \: D =13 .892}[/tex]
Thus, Distance between the two given points will be √193 or √13.892 units.
Answer:
[tex]\bf \sqrt{193}[/tex] units or 13.9 units is the distance.
Explanation:
[tex]\sf Distance \ between \ two \ points = \sqrt{(x_2 - x_1)^2 +(y_2 - y_1)^2}[/tex]
Given points: (7, 4) and (-5, -3)
Identify following:
[tex]\sf x_2= 7[/tex], [tex]\sf x_1 = -5[/tex], [tex]\sf y_2 =4[/tex], [tex]\sf y_1 =-3[/tex]
Find distance:
[tex]\rightarrow \sf \sqrt{(7 - (-5))^2 + (4 - (-3))^2} \quad = \quad \sqrt{144+49} \quad = \quad \sqrt{193} \quad \approx \ 13.9[/tex]