Find the equivalent resistance of this circuit. First, what is the equivalent resistance, Req(23), of the parallel combination of R2 and R3?

[tex]R_{eq(23)} = \left(\dfrac 1{R_2} + \dfrac{1}{R_3}\right)^{-1}\\\\\\~~~~~~~~~= \left( \dfrac 1{200} + \dfrac 1{300} \right)^{-1}\\\\~~~~~~~~~=\left( \dfrac{5}{600} \right)^{-1}\\\\\\~~~~~~~~~=\dfrac{600}5\\\\\\~~~~~~~~~= 120~ \Omega[/tex]
Step-by-step explanation :
Here we have to calculate the equivalent resistance of the parallel combination between R2 and R3.
As we know that,
>> 1/Rp = (1/200) + (1/300)
>> 1/Rp = (300 + 200 / 600)
>> 1/Rp = 500 / 600
>> 1/Rp = 5 / 6
>> Rp = 6 / 5
>> Rp = 1.2Ω
Therefore,